1856 United States presidential election in Texas

Summary

The 1856 United States presidential election in Texas was held on Tuesday November 4, as part of the 1856 United States presidential election. State voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.

1856 United States presidential election in Texas

← 1852 November 4, 1856 1860 →
 
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew J. Donelson
Electoral vote 4 0
Popular vote 31,169 15,639
Percentage 66.59% 33.41%

County Results

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

Texas voted for the Democratic nominee James Buchanan, who received 67% of the vote. Texas was Buchanan's second-strongest state.

Republican Party nominee John C. Frémont was not on the ballot. Texas would never be won by a Republican candidate until Herbert Hoover narrowly won the state in 1928.[1]

Results edit

1856 United States presidential election in Texas[2]
Party Candidate Votes Percentage Electoral votes
Democratic James Buchanan 31,169 66.589% 4
Know-Nothing Millard Fillmore 15,639 33.411% 0
Total 46,808 100.0% 4

See also edit

References edit

  1. ^ "Republican Party". Britannica Kids. Retrieved 2023-12-22.
  2. ^ "David Leip's Atlas of U.S. Presidential Elections".