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1998 United States House of Representatives elections in Arizona 
Summary
The 1998 congressional elections in Arizona were elections for Arizona's delegation to the United States House of Representatives, which occurred along with congressional elections nationwide on November 7, 1998. Arizona has six seats, as apportioned during the 1990 United States census. Republicans held five seats and Democrats held one seat.
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All 6 Arizona seats to the United States House of Representatives | |||||||||||||||||||||||||
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Overview edit
| 1998 United States House of Representatives elections in Arizona[1] | |||||
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| Party | Votes | Percentage | Seats | +/– | |
| Republican | 573,651 | 57.15% | 5 | - | |
| Democratic | 406,834 | 40.53% | 1 | - | |
| Libertarian | 18,042 | 1.80% | 0 | - | |
| Others | 5,239 | 0.52% | 0 | - | |
| Totals | 1,003,766 | 100.00% | 6 | - | |
References edit
- ^ "Statistics report" (PDF). clerk.house.gov. 1998. Retrieved March 30, 2021.