1990 Iowa gubernatorial election

Summary

The 1990 Iowa gubernatorial election took place November 8, 1990. Incumbent Republican Governor of Iowa Terry Branstad ran for re-election to a third term as governor. On the Democratic side, state representative Donald Avenson won his party's nomination and both Branstad and Avenson moved on to the general election. Branstad won re-election to a third term as governor, defeating Avenson by a margin of over 20 points.

1990 Iowa gubernatorial election

← 1986 November 8, 1990 1994 →
 
Nominee Terry Branstad Donald Avenson
Party Republican Democratic
Popular vote 591,852 379,372
Percentage 60.6% 38.9%

County results

Branstad:      50-60%      60-70%      70-80%      80-90%

Avenson:      50–60%

Governor before election

Terry Branstad
Republican

Elected Governor

Terry Branstad
Republican

Democratic primary edit

Candidates edit

Results edit

Democratic primary results[1]
Party Candidate Votes %
Democratic Donald Avenson 79,022 39.45
Democratic Tom Miller 63,364 31.63
Democratic John Crystal 52,170 26.05
Democratic Jo Ann Zimmerman 4,475 2.23
Democratic Darold Powers 1,167 0.58
Democratic Write-ins 107 0.05
Total votes 200,305 100.00

Republican primary edit

Candidates edit

Results edit

Republican primary results[1]
Party Candidate Votes %
Republican Terry Branstad (inc.) 94,253 99.52
Republican Write-ins 453 0.47
Total votes 94,706 100.00

General election edit

Results edit

Iowa gubernatorial election, 1990[2]
Party Candidate Votes % ±%
Republican Terry Branstad (inc.) 591,852 60.61% +8.70%
Democratic Donald Avenson 379,372 38.85% -9.14%
Socialist Workers Nan Bailey 4,263 0.44%
Write-ins 996 0.10%
Turnout 976,483
Republican hold Swing

See also edit

References edit

  1. ^ a b "PRIMARY ELECTION : June 5,1990 : OFFICIAL CANVASS SUMMARY" (PDF). Sos.iowa.gov. Retrieved July 5, 2018.
  2. ^ "Archived copy" (PDF). Archived from the original (PDF) on December 4, 2018. Retrieved July 4, 2018.{{cite web}}: CS1 maint: archived copy as title (link)