1966 United States Senate election in Montana

Summary

The 1966 United States Senate election in Montana took place on November 8, 1966. Incumbent United States Senator Lee Metcalf, who was first elected to the Senate in 1960, ran for re-election. He won the Democratic primary uncontested, and moved on to the general election, where he was opposed by Tim M. Babcock, the Republican nominee and the Governor of Montana. Though the race remained close, Metcalf was able to expand on his 1960 margin of victory, and defeated Babcock to win a second term.

1966 United States Senate election in Montana

← 1960 November 8, 1966 1972 →
 
Nominee Lee Metcalf Tim Babcock
Party Democratic Republican
Popular vote 138,166 121,697
Percentage 53.17% 46.83%

County results
Metcalf:      50–60%      60–70%      70–80%
Babcock:      50–60%      60–70%

U.S. senator before election

Lee Metcalf
Democratic

Elected U.S. Senator

Lee Metcalf
Democratic

Democratic primary edit

Candidates edit

Results edit

Democratic Party primary results[1]
Party Candidate Votes %
Democratic Lee Metcalf (incumbent) 73,975 100.00%
Total votes 73,975 100.00%

Republican primary edit

Candidates edit

Results edit

Republican Primary results[1]
Party Candidate Votes %
Republican Tim M. Babcock 54,828 100.00%
Total votes 54,828 100.00%

General election edit

Results edit

United States Senate election in Montana, 1966[2]
Party Candidate Votes % ±%
Democratic Lee Metcalf (incumbent) 138,166 53.17% +2.44%
Republican Tim M. Babcock 121,697 46.83% -2.44%
Majority 16,469 6.34% +4.87%
Turnout 259,863
Democratic hold Swing

See also edit

References edit

  1. ^ a b "Report of the Official Canvass of the Vote Cast at the Primary Election Held in the State of Montana, August 16, 1966". Montana Secretary of State. Retrieved July 2, 2014.
  2. ^ "Statistics of the Congressional Election of November 8, 1966" (PDF). Clerk of the United States House of Representatives. Retrieved July 2, 2014.