1960 United States presidential election in Delaware

Summary

The 1960 United States presidential election in Delaware took place on November 8, 1960, as part of the 1960 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

1960 United States presidential election in Delaware

← 1956 November 8, 1960[1] 1964 →
 
Nominee John F. Kennedy Richard Nixon
Party Democratic Republican
Home state Massachusetts California
Running mate Lyndon B. Johnson Henry Cabot Lodge Jr.
Electoral vote 3 0
Popular vote 99,590 96,373
Percentage 50.63% 49.00%

County Results

President before election

Dwight D. Eisenhower
Republican

Elected President

John F. Kennedy
Democratic

Delaware was won by Senator John F. Kennedy (DMassachusetts), running with Senator Lyndon B. Johnson, with 50.63% of the popular vote against incumbent Vice President Richard Nixon (RCalifornia), running with United States Ambassador to the United Nations Henry Cabot Lodge Jr., with 49.00% of the popular vote.[3][4]

Results edit

1960 United States presidential election in Delaware
Party Candidate Votes %
Democratic John F. Kennedy 99,590 50.63%
Republican Richard Nixon 96,373 49.00%
Write-in 720 0.37%
Total votes 196,683 100.00%

See also edit

References edit

  1. ^ "United States Presidential election of 1960 - Encyclopædia Britannica". Retrieved June 7, 2017.
  2. ^ "1960 Election for the Forty-Fourth Term (1961-65)". Retrieved June 7, 2017.
  3. ^ "1960 Presidential General Election Results - Delaware". Retrieved June 7, 2017.
  4. ^ "The American Presidency Project - Election of 1960". Retrieved June 7, 2017.