The 1940 United States presidential election in New Hampshire took place on November 5, 1940. All contemporary 48 states were part of the 1940 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.

1940 United States presidential election in New Hampshire

← 1936 November 5, 1940 1944 →

Nominee Franklin D. Roosevelt Wendell Willkie Party Democratic Republican Home state New York New York Running mate Henry A. Wallace Charles L. McNary Electoral vote 4 0 Popular vote 125,292 110,127 Percentage 53.22% 46.78%

County Results Roosevelt   50-60%   60-70% Willkie   50-60%   60-70%

President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

New Hampshire was won by incumbent Democratic President Franklin D. Roosevelt of New York, who was running against Republican businessman Wendell Willkie of New York. Roosevelt ran with Henry A. Wallace of Iowa as his running mate, and Willkie ran with Senator Charles L. McNary of Oregon.

Roosevelt won New Hampshire by 6.44%, at the time the best performance by a Democratic presidential candidate in this traditionally Republican state since the latter party was founded^[1] and the first time since Franklin Pierce in 1852 that a Democrat won the state with an absolute majority of the vote. (It had been won with a plurality by Roosevelt four years earlier and by Woodrow Wilson in 1912 and 1916.) Roosevelt's gain in New Hampshire and other New England states, in an election when Willkie carried almost seven hundred counties that the President had won during his landslide four years beforehand, was due to support in the region for helping Britain and France during World War II.^[2]