1916 Vermont gubernatorial election

Summary

The 1916 Vermont gubernatorial election took place on November 7, 1916. Incumbent Republican Charles W. Gates, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Horace F. Graham defeated Democratic candidate William B. Mayo to succeed him.

1916 Vermont gubernatorial election

← 1914 November 7, 1916 (1916-11-07) 1918 →
 
Nominee Horace F. Graham William B. Mayo
Party Republican Democratic
Popular vote 43,265 15,789
Percentage 71.1% 25.9%

County results
Graham:      60–70%      70–80%      80–90%

Governor before election

Charles W. Gates
Republican

Elected Governor

Horace F. Graham
Republican

Republican primary edit

Results edit

Republican primary results[2]
Party Candidate Votes % ±%
Republican Horace F. Graham 33,244 99.9
Republican Other 37 0.1
Total votes '33,281' '100'

Democratic primary edit

Results edit

Democratic primary results[2]
Party Candidate Votes % ±%
Democratic William B. Mayo 3,562 99.9
Democratic Other 1 0.0
Total votes '3,563' '100'

General election edit

Results edit

1916 Vermont gubernatorial election[3]
Party Candidate Votes % ±%
Republican Horace F. Graham 43,265 71.1
Democratic William B. Mayo 15,789 25.9
Socialist W. R. Rowland 920 1.5
Prohibition Lester W. Hanson 876 1.4
N/A Other 4 0.0
Total votes '60,854' '100'

References edit

  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
  2. ^ a b "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on January 1, 2015. Retrieved January 1, 2015.
  3. ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.