1900 United States presidential election in Vermont

Summary

The 1900 United States presidential election in Vermont took place on November 6, 1900 as part of the 1900 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

1900 United States presidential election in Vermont

← 1896 November 6, 1900 1904 →
 
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai E. Stevenson
Electoral vote 4 0
Popular vote 42,569 12,849
Percentage 75.73% 22.86%

County Results
McKinley
  60-70%
  70-80%
  80-90%


President before election

William McKinley
Republican

Elected President

William McKinley
Republican

Vermont overwhelmingly voted for the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. They defeated the Democratic nominees, former U.S. Representative and 1896 Democratic presidential nominee William Jennings Bryan and his running mate, former Vice President Adlai Stevenson I. McKinley won Vermont by a landslide margin of 52.87% in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.

Four years earlier, McKinley had won Vermont with 80.08% of the popular vote, making it his strongest victory in the 1896 presidential election in terms of percentage in the popular vote as well as the best performance of any presidential candidate in Vermont to date. Vermont would once again be McKinley's strongest state in popular vote percentage, though with a slightly reduced margin of 75.73%.[1]

Bryan had previously lost Vermont to McKinley four years earlier and would later lose the state again in 1908 to William Howard Taft.

Results edit

1900 United States presidential election in Vermont[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William McKinley of Ohio Theodore Roosevelt of New York 42,569 75.73% 4 100.00%
Democratic William Jennings Bryan of Nebraska Adlai Ewing Stevenson I of Illinois 12,849 22.86% 0 0.00%
Prohibition John Granville Woolley of Illinois Henry Brewer Metcalf of Rhode Island 383 0.68% 0 0.00%
Populist Wharton Barker of Pennsylvania Ignatius Loyola Donnelly of Minnesota 367 0.65% 0 0.00%
N/A Others Others 44 0.06% 0 0.00%
Total 56,212 100.00% 4 100.00%

Results by county edit

County William McKinley
Republican
William Jennings Bryan
Democratic
Various candidates
Other parties
Margin Total votes cast[3]
# % # % # % # %
Addison 3,286 86.41% 467 12.28% 50 1.31% 2,819 74.13% 3,803
Bennington 2,666 74.57% 871 24.36% 38 1.06% 1,795 50.21% 3,575
Caledonia 2,957 76.79% 817 21.22% 77 2.00% 2,140 55.57% 3,851
Chittenden 3,907 67.26% 1,822 31.37% 80 1.38% 2,085 35.89% 5,809
Essex 758 67.50% 358 31.88% 7 0.62% 400 35.62% 1,123
Franklin 2,738 66.38% 1,316 31.90% 71 1.72% 1,422 34.47% 4,125
Grand Isle 356 68.86% 146 28.24% 15 2.90% 210 40.62% 517
Lamoille 1,742 79.15% 418 18.99% 41 1.86% 1,324 60.15% 2,201
Orange 2,515 75.32% 740 22.16% 84 2.52% 1,775 53.16% 3,339
Orleans 2,749 85.24% 441 13.67% 35 1.09% 2,308 71.57% 3,225
Rutland 5,901 74.66% 1,874 23.71% 129 1.63% 4,027 50.95% 7,904
Washington 3,819 68.94% 1,622 29.28% 99 1.79% 2,197 39.66% 5,540
Windham 3,948 79.02% 1,014 20.30% 34 0.68% 2,934 58.73% 4,996
Windsor 5,227 84.25% 943 15.20% 34 0.55% 4,284 69.05% 6,204
Totals 42,569 75.73% 12,849 22.86% 794 1.41% 29,720 52.87% 56,212

See also edit

References edit

  1. ^ "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1900 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved December 23, 2013.
  3. ^ Robinson, Edgar Eugene; The Presidential Vote 1896-1932, pp. 352-354 ISBN 9780804716963