1896 United States presidential election in Texas

Summary

The 1896 United States presidential election in Texas took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose 15 electors to the Electoral College, which selected the president and vice president.

1896 United States presidential election in Texas

← 1892 November 3, 1896 1900 →
 
Nominee William Jennings Bryan William McKinley
Party Democratic Republican
Alliance Populist
Home state Nebraska Ohio
Running mate Arthur Sewall Garret Hobart
Electoral vote 15 0
Popular vote 370,434 167,520
Percentage 68.00% 30.75%

County Results

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

Texas was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. Four electors cast their vice presidential ballots for Thomas E. Watson.

Bryan would later win Texas again in both 1900 and 1908.

Results edit

1896 United States presidential election in Texas[1]
Party Candidate Votes Percentage Electoral votes
Democratic William Jennings Bryan 370,434 68.00% 15
Republican William McKinley 167,520 30.75% 0
National Democratic John M. Palmer 5,046 0.93% 0
Prohibition Joshua Levering 1,786 0.33% 0
Totals 544,786 100.00% 15
Voter turnout

See also edit

Notes edit

References edit

  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Texas