1872 United States presidential election in Nebraska

Summary

The 1872 United States presidential election in Nebraska took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

1872 United States presidential election in Nebraska

← 1868 November 5, 1872 1876 →
 
Nominee Ulysses S. Grant Horace Greeley
Party Republican Liberal Republican
Home state Illinois New York
Running mate Henry Wilson Benjamin G. Brown
Electoral vote 3 0
Popular vote 18,329 7,603
Percentage 70.68% 29.32%

County Results

President before election

Ulysses S. Grant
Republican

Elected President

Ulysses S. Grant
Republican

Nebraska voted for the Republican candidate, Ulysses S. Grant, over Liberal Republican candidate Horace Greeley. Grant won Nebraska by a margin of 41.36%.

With 70.68% of the popular vote, Nebraska would be Grant's fourth strongest victory in terms of percentage in the popular vote after Vermont, South Carolina and Rhode Island. Grant’s victory is, as of 2024, the best showing for any candidate, and by extension, party.[1]

Results edit

1872 United States presidential election in Nebraska[2][3]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Henry Wilson of Massachusetts 18,329 70.68% 3 100.00%
Liberal Republican Horace Greely of New York Benjamin Gratz Brown of Missouri 7,603 29.32% 0 0.00%
Total 25,932 100.00% 3 100.00%

See also edit

References edit

  1. ^ "1872 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1872 Presidential General Election Results - Nebraska". U.S. Election Atlas. Retrieved December 3, 2017.
  3. ^ "1872 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.