1864 United States presidential election in West Virginia

Summary

The 1864 United States presidential election in West Virginia took place on November 8, 1864, as part of the 1864 United States presidential election. West Virginia voters chose five representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

1864 United States presidential election in West Virginia

← 1860 (Virginia) November 8, 1864 1868 →
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 5 0
Popular vote 23,799 11,078
Percentage 68.24% 31.76%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

This was the first time that West Virginia participated in an election since gaining statehood, as it had been admitted as the 34th state on June 20, 1863. The state would be won by the incumbent President Abraham Lincoln of Illinois, running on the National Union ticket with former Senator and Military Governor of Tennessee Andrew Johnson. They defeated the Democratic candidate 4th Commanding General of the United States Army George B. McClellan of New Jersey and his running mate Representative George H. Pendleton of Ohio.[1] Lincoln won the state by a margin of 36.48%.

With 68.24% of the popular vote, West Virginia would prove to be Lincoln's fifth strongest state in terms of popular vote percentage after Kansas, Vermont, Massachusetts and Missouri.[2]

Results edit

1864 United States presidential election in West Virginia[1]
Party Candidate Votes %
National Union Abraham Lincoln (incumbent) 23,799 68.24%
Democratic George B. McClellan 11,078 31.76%
Total votes 34,877 100.00%

References edit

  1. ^ a b c "1864 Presidential Election Results West Virginia".
  2. ^ "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.