1864 United States presidential election in New Jersey

Summary

The 1864 United States presidential election in New Jersey took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

1864 United States presidential election in New Jersey

← 1860 November 8, 1864 1868 →
 
Nominee George B. McClellan Abraham Lincoln
Party Democratic National Union
Home state New Jersey Illinois
Running mate George H. Pendleton Andrew Johnson
Electoral vote 7 0
Popular vote 68,024 60,723
Percentage 52.84% 47.16%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

New Jersey voted for the Democratic candidate, George B. McClellan, over the National Union candidate, incumbent president Abraham Lincoln. McClellan won his home state by a narrow margin of 5.68%. New Jersey was one of the three states McClellan won, with the other two being neighboring Delaware and Kentucky.

With 52.84% of the popular vote, New Jersey would prove to be McClellan's second strongest after Kentucky.[1]


Results edit

1864 United States presidential election in New Jersey[2]
Party Candidate Votes Percentage Electoral votes
Democratic George B. McClellan 68,024 52.84% 7
National Union Abraham Lincoln (incumbent) 60,723 47.16% 0
Totals 128,747 100.0% 7

See also edit

References edit

  1. ^ "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1864 Presidential General Election Results - New Jersey".