1864 United States presidential election in Connecticut

Summary

The 1864 United States presidential election in Connecticut took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

1864 United States presidential election in Connecticut

← 1860 November 8, 1864 1868 →
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 6 0
Popular vote 44,693 42,288
Percentage 51.38% 48.62%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

Connecticut voted for the National Union candidate, Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate, George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a narrow margin of 2.76%.

Although he lost the state, Connecticut would prove to be McClellan's fifth strongest state after Kentucky, New Jersey, Delaware and New York.[1]

Results edit

1864 United States presidential election in Connecticut[2]
Party Candidate Votes Percentage Electoral votes
National Union Abraham Lincoln (incumbent) 44,693 51.38% 6
Democratic George B. McClellan 42,288 48.62% 0
Totals 86,981 100.0% 6

See also edit

References edit

  1. ^ "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1864 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved December 24, 2013.