1860 United States presidential election in South Carolina

Summary

The 1860 United States presidential election in South Carolina took place on November 6, 1860, as part of this 1860 United States presidential election. The state legislature chose eight representatives, or electors to the Electoral College, who voted for president and vice president. By 1860, South Carolina was the only state using this procedure in a presidential election and would be the last time the state would do so.

1860 United States presidential election in South Carolina

← 1856 November 6, 1860 1868 →
 
Nominee John C. Breckinridge
Party Southern Democratic
Home state Kentucky
Running mate Joseph Lane
Electoral vote 8

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

South Carolina cast eight electoral votes for the Southern Democratic candidate John C. Breckinridge. These electors were chosen by the South Carolina General Assembly, the state legislature, rather than by popular vote.[1] However, Republican Party candidate Abraham Lincoln would win the election nationally and would cause a major upset in the Southern States. South Carolina would be the first state to secede from the Union, on December 20, 1860, and would join the newly formed Confederate States of America in the February of the following year. South Carolina would not vote in another presidential election until 1868.

Results edit

1860 United States presidential election in South Carolina[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Southern Democratic John Cabell Breckinridge of Kentucky Joseph Lane of Oregon 8 100.00%

References edit

  1. ^ a b "1860 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 23, 2013.