1860 United States presidential election in Oregon

Summary

The 1860 United States presidential election in Oregon took place on November 6, 1860, as part of the 1860 United States presidential election. Oregon voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

1860 United States presidential election in Oregon

November 6, 1860 1864 →
 
Nominee Abraham Lincoln John C. Breckinridge Stephen A. Douglas
Party Republican Southern Democratic Democratic
Home state Illinois Kentucky Illinois
Running mate Hannibal Hamlin Joseph Lane Herschel V. Johnson
Electoral vote 3 0 0
Popular vote 5,344 5,074 4,131
Percentage 36.20% 34.37% 27.99%

County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Oregon voted in its first ever presidential election, having become the 33rd state on February 14, 1859. The state was won by the Republican nominee, Illinois Representative Abraham Lincoln and his running mate Senator Hannibal Hamlin of Maine. They defeated the Southern Democratic nominee 14th Vice President of the United States John C. Breckinridge of Kentucky and his running mate Senator Joseph Lane of Oregon as well as Democratic nominee Senator Stephen A. Douglas of Illinois and his running mate 41st Governor of Georgia Herschel V. Johnson. Lincoln won the state by a narrow margin of 1.83%.

Oregon was the only state where the first and second-place finishers matched the first and second place national finishers in the electoral college (Lincoln first, then Breckenridge in second).

Results edit

1860 United States presidential election in Oregon[1]
Party Candidate Votes %
Republican Abraham Lincoln 5,344 36.20%
Southern Democratic John C. Breckinridge 5,074 34.37%
Democratic Stephen A. Douglas 4,131 27.99%
Constitutional Union John Bell 212 1.44%
Total votes 14,761 100%

See also edit

References edit

  1. ^ "1860 Presidential Election Results Oregon".