1860 United States presidential election in Connecticut

Summary

The 1860 United States presidential election in Connecticut took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose six electors of the Electoral College, who voted for president and vice president.

1860 United States presidential election in Connecticut

← 1856 November 2, 1860 1864 →
 
Nominee Abraham Lincoln Stephen A. Douglas John C. Breckinridge
Party Republican Democratic Southern Democratic
Home state Illinois Illinois Kentucky
Running mate Hannibal Hamlin Herschel V. Johnson Joseph Lane
Electoral vote 6 0 0
Popular vote 43,486 17,364 16,558
Percentage 53.86% 21.50% 20.51%

County Results
Lincoln
  30–40%
  40–50%
  50-60%
  60-70%
  70-80%
  80-90%

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Connecticut was won by Republican candidate Abraham Lincoln, who won by a margin of 32.36%.

Results edit

1860 United States presidential election in Connecticut[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 43,486 53.86% 6 100.00%
Democratic Stephen Arnold Douglas of Illinois Herschel Vespasian Johnson of Georgia 17,364 21.50% 0 0.00%
Southern Democratic John Cabell Breckinridge of Kentucky Joseph Lane of Oregon 16,558 20.51% 0 0.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 3,337 4.13% 0 0.00%
Total 80,745 100.00% 6 100.00%

See also edit

References edit

  1. ^ "1860 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved December 24, 2013.