1860 United States presidential election in Arkansas

Summary

The 1860 United States presidential election in Arkansas took place on November 6, 1860, as part of the 1860 United States presidential election. Arkansas voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

1860 United States presidential election in Arkansas

← 1856 November 6, 1860 1868 →
 
Nominee John C. Breckinridge John Bell Stephen A. Douglas
Party Southern Democratic Constitutional Union Democratic
Home state Kentucky Tennessee Illinois
Running mate Joseph Lane Edward Everett Herschel V. Johnson
Electoral vote 4 0 0
Popular vote 28,732 20,063 5,357
Percentage 53.06% 37.05% 9.89%

County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Arkansas was won by the Southern Democratic candidate 14th Vice President of the United States John C. Breckinridge of Kentucky and his running mate Senator Joseph Lane of Oregon. They defeated the Constitutional Union candidate Senator John Bell of Tennessee and his running mate Governor of Massachusetts Edward Everett as well as Democratic candidate Senator Stephen A. Douglas of Illinois and his running mate 41st Governor of Georgia Herschel V. Johnson. Breckinridge won the state by a margin of 16.01%.

Republican Party candidate Abraham Lincoln was not on the ballot in the state.

Results edit

1860 United States presidential election in Arkansas[1]
Party Candidate Votes %
Southern Democratic John C. Breckinridge 28,732 53.06%
Constitutional Union John Bell 20,063 37.05%
Democratic Stephen A. Douglas 5,357 9.89%
Total votes 54,152 100%

See also edit

References edit

  1. ^ "1860 Presidential Election Results Arkansas".