1856 United States presidential election in North Carolina

Summary

The 1856 United States presidential election in North Carolina took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

1856 United States presidential election in North Carolina

← 1852 November 4, 1856 1860 →
 
Nominee James Buchanan Millard Fillmore
Party Democratic Whig
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew J. Donelson
Electoral vote 10 0
Popular vote 48,243 36,720
Percentage 56.78% 43.22%

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

North Carolina voted for the Democratic candidate, James Buchanan, over Whig candidate Millard Fillmore. Fillmore ran under the American Party ticket in most states, but ran as a Whig in North Carolina after receiving the endorsement of the party at the 1856 Whig National Convention.[1] Buchanan won North Carolina by a margin of 13.56%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Results edit

1856 United States presidential election in North Carolina[2][3]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 48,243 56.78% 10 100.00%
Whig Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 36,720 43.22% 0 0.00%
Total 84,963 100.00% 10 100.00%

References edit

  1. ^ "Whig Party Platform of 1856". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.
  2. ^ "1856 Presidential General Election Results - North Carolina". U.S. Election Atlas. Retrieved December 3, 2017.
  3. ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.