1852 United States presidential election in Wisconsin

Summary

The 1852 United States presidential election in Wisconsin was held on November 2, 1852, as part of the 1852 United States presidential election. State voters chose five electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Wisconsin

← 1848 November 2, 1852 1856 →
 
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George W. Julian
Electoral vote 5 0 0
Popular vote 33,658 22,210 8,814
Percentage 52.04% 34.34% 13.63%

County Results

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

Democratic Party candidate Franklin Pierce won the state with 52.04 percent of the popular vote, winning Wisconsin's five electoral votes.[1]

This would be the final time a Democratic presidential candidate would win Wisconsin until Grover Cleveland won the state in 1892. No Democratic presidential candidate would again win a majority of Wisconsin's popular vote until Franklin D. Roosevelt in 1932.

Results edit

1852 United States presidential election in Wisconsin
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William Rufus DeVane King of Alabama 33,658 52.04% 5 100.00%
Whig Winfield Scott of New Jersey William Alexander Graham of North Carolina 22,210 34.34% 0 0.00%
Free Soil John Parker Hale of New Hampshire George Washington Julian of Indiana 8,814 13.63% 0 0.00%
Total 64,682 100.00% 5 100.00%

See also edit

References edit

  1. ^ "1852 Presidential General Election Results – Wisconsin". Retrieved August 17, 2016.