1840 United States presidential election in Virginia

Summary

The 1840 United States presidential election in Virginia took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.

1840 United States presidential election in Virginia

← 1836 October 30 – December 2, 1840 1844 →
 
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard M. Johnson John Tyler
Electoral vote 23 0
Popular vote 43,757 42,637
Percentage 50.65% 49.35%

County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

Virginia voted for the Democratic candidate, incumbent President Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren narrowly won Virginia by a margin of 1.3%, or 1,120 votes.

Results edit

1840 United States presidential election in Virginia[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren (inc.) 43,757 50.65% 23
Whig William Henry Harrison 42,637 49.35% 0
Totals 86,394 100.0% 23

References edit

  1. ^ "1840 Presidential General Election Results - Virginia". U.S. Election Atlas. Archived from the original on June 19, 2015. Retrieved April 12, 2013.