The 1840 United States presidential election in Indiana took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

1840 United States presidential election in Indiana

← 1836 October 30 - December 2, 1840 1844 →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 9 0 Popular vote 65,302/65,280 51,604/51,696 Percentage 55.86%/55.79 44.14%/44.18%

County Results Harrison   50-60%   60-70%   70–80% Van Buren   50-60%   60-70%   70-80%   80-90% Unknown/No vote

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

Indiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Indiana by a margin of 11.72%./11.61%