1836 United States presidential election in Mississippi

Summary

The 1836 United States presidential election in Mississippi took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Mississippi

← 1832 November 3 – December 7, 1836 1840 →
 
Nominee Martin Van Buren Hugh White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard Johnson John Tyler
Electoral vote 4 0
Popular vote 10,297 9,782
Percentage 51.28% 48.72%

Mississippi voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Mississippi by a margin of 2.56%.

Results edit

United States presidential election in Mississippi, 1836[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 10,297 51.28% 4
Whig Hugh White 9,782 48.72% 0
Totals 20,079 100.0% 4

References edit

  1. ^ "1836 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved April 15, 2013.