1832 United States presidential election in Tennessee

Summary

The 1832 United States presidential election in Tennessee took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

1832 United States presidential election in Tennessee
← 1828 November 2 – December 5, 1832 1836 →
 
Nominee Andrew Jackson Henry Clay
Party Democratic National Republican
Home state Tennessee Kentucky
Running mate Martin Van Buren John Sergeant
Electoral vote 15 0
Popular vote 28,078 1,347
Percentage 95.42% 4.58%

Precinct before election

Andrew Jackson
Democratic

Elected Precinct

Andrew Jackson
Democratic

Tennessee voted for the Democratic Party candidate, state native Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Tennessee by a large margin of 90.84 percent. This is the most recent election in which Blount County, Carter County, Cocke County, Grainger County, Jefferson County, and Sevier County voted for a Democratic presidential candidate.

Results edit

1832 United States presidential election in Tennessee[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson (incumbent) 28,078 95.42% 15
National Republican Henry Clay 1,347 4.58% 0
Totals 26,731 100.0% 15

References edit

  1. ^ "1832 Presidential General Election Results — Tennessee". U.S. Election Atlas. Retrieved April 12, 2013.