1828 United States presidential election in Tennessee

Summary

The 1828 United States presidential election in Tennessee took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

1828 United States presidential election in Tennessee
← 1824 October 31 – December 2, 1828 1832 →
 
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 11 0
Popular vote 44,293 2,240
Percentage 95.19% 4.81%

President before election

John Quincy Adams
National Republican

Elected President

Andrew Jackson
Democratic

Tennessee voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Tennessee, his home state, by a wide margin of 90.38%. This is the last time any party swept every Tennessee county.

Results edit

1828 United States presidential election in Tennessee[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 44,293 95.19% 11
National Republican John Quincy Adams (incumbent) 2,240 4.81% 0
Totals 46,533 100.0% 11

References edit

  1. ^ "1828 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved February 28, 2013.