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1828 United States presidential election in Indiana 
Summary
The 1828 United States presidential election in Indiana took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
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Indiana voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Indiana by a margin of 13.24%.
Results edit
| 1828 United States presidential election in Indiana[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Andrew Jackson | 22,257 | 56.62% | 5 | |
| National Republican | John Quincy Adams (incumbent) | 17,052 | 43.38% | 0 | |
| Totals | 39,309 | 100.0% | 5 | ||
See also edit
References edit
- ^ "1828 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved February 28, 2013.