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1826 United States Senate election in Pennsylvania

1826 United States Senate election in Pennsylvania

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The 1826 United States Senate election in Pennsylvania was held on December 12, 1826. Isaac D. Barnard was elected by the Pennsylvania General Assembly to the United States Senate.[1]

Results

The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on December 12, 1826, to elect a Senator to serve the term beginning on March 4, 1827. Two ballots were recorded. The results of the second and final ballot of both houses combined are as follows:

State Legislature Results[1]
Party Candidate Votes %
Jacksonian Isaac D. Barnard 108 81.20
Jacksonian Samuel D. Ingham 11 8.27
Jacksonian Joseph Hemphill 5 3.76
Jacksonian James Buchanan 3 2.26
Jacksonian Thomas Sergeant 1 0.75
N/A Not voting 5 3.76
Totals 133 100.00%

References

  1. ^ a b "U.S. Senate Election - 12 December 1826" (PDF). Wilkes University. Retrieved 21 December 2012.

External links

Preceded by
1820-21
Pennsylvania U.S. Senate election (Class I)
1826
Succeeded by
1831


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