1824 United States presidential election in Vermont

Summary

The 1824 United States presidential election in Vermont took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. The state legislature chose seven representatives, or electors (the last time they would do this in Vermont) to the Electoral College, who voted for President and Vice President.[1]

1824 United States presidential election in Vermont

← 1820 October 26 – December 2, 1824 1828 →
 
Nominee John Quincy Adams
Party Democratic-Republican
Home state Massachusetts
Running mate John C. Calhoun
Electoral vote 7

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Vermont cast seven electoral votes for New England native John Quincy Adams.

Results edit

1824 United States presidential election in Vermont[2]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican John Quincy Adams 7
Democratic-Republican Henry Clay 0
Democratic-Republican William H. Crawford 0
Democratic-Republican Andrew Jackson 0
Totals 7

See also edit

References edit

  1. ^ Moore, John L., ed. (1985). Congressional Quarterly's Guide to U.S. Elections (2nd ed.). Washington, D.C.: Congressional Quarterly, Inc. pp. 254–56.
  2. ^ "Electoral Votes for President and Vice President 1821-1837". National Archives and Records Administration. Retrieved February 28, 2013.