1824 United States presidential election in Mississippi

Summary

The 1824 United States presidential election in Mississippi took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in Mississippi

← 1820 October 26 – December 2, 1824 1828 →
 
Nominee Andrew Jackson John Quincy Adams
Party Democratic-Republican Democratic-Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun John C. Calhoun
Electoral vote 3 0
Popular vote 3,121 1,654
Percentage 63.77% 33.80%


President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Mississippi voted for Andrew Jackson over John Quincy Adams, William H. Crawford and Henry Clay. Jackson won Mississippi by a margin of 29.97%.

Results edit

United States presidential election in Mississippi, 1824[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Andrew Jackson 3,121 63.77% 3
Democratic-Republican John Quincy Adams 1,654 33.80% 0
Democratic-Republican William H. Crawford 119 2.43% 0
Totals 4,894 100.0% 3

References edit

  1. ^ "1824 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved February 27, 2013.