1822 Ohio gubernatorial election

Summary

The 1822 Ohio gubernatorial election was held on October 8, 1822. Incumbent Democratic Governor of Ohio William Medill became governor after the resignation of Reuben Wood to accept a Senate seat, leaving Speaker of the Senate Allen Trimble to act as governor. Former Senator, and 1820 gubernatorial challenger Jeremiah Morrow narrowly beat Trimble and former Ohio Supreme Court Justice William Irvin.

1822 Ohio gubernatorial election

← 1820 October 8, 1822 1824 →
 
Nominee Jeremiah Morrow Allen Trimble William W. Irvin
Party Democratic-Republican Democratic-Republican Democratic-Republican
Popular vote 26,059 22,899 11,050
Percentage 41.06% 36.08% 17.41%

Election results by county
Morrow:      50-60%      60-70%      70-80%      80-90%      90-100%
Trimble:      30-40%      40-50%      50-60%      60-70%      80-90%      90-100%
Irvin:      40-50%      60-70%      70-80%      80-90%      90-100%
Unknown/no votes:      

Governor before election

Allen Trimble
Democratic-Republican

Elected Governor

Jeremiah Morrow
Democratic-Republican

General election edit

Results edit

Ohio gubernatorial election, 1822[1]
Party Candidate Votes % ±%
Democratic-Republican Jeremiah Morrow 26,059 41.06%
Democratic-Republican Allen Trimble (incumbent) 22,899 36.08%
Democratic-Republican William W. Irvin 11,050 17.41%
Other Others 3,462 5.46%
Majority 3,160 4.98%
Turnout 63,470
Democratic-Republican hold Swing

References edit

  1. ^ "Our Campaigns – OH Governor Race – Oct 08, 1822". ourcampaigns.com. Retrieved March 31, 2015.