1820 United States presidential election in Pennsylvania

Summary

The 1820 United States presidential election in Pennsylvania took place as part of the 1820 United States presidential election. Voters chose 25 representatives, or electors to the Electoral College, who voted for President and Vice President. Only 24 electoral votes were cast from Pennsylvania, however, due to one of the electors having died.[1]

1820 United States presidential election in Pennsylvania

← 1816 November 1 – December 6, 1820 1824 →
 
Nominee James Monroe DeWitt Clinton
Party Democratic-Republican Independent
Home state Virginia New York
Running mate Daniel D. Tompkins -
Electoral vote 24 0
Popular vote 30,313 1,893
Percentage 94.12% 5.88%

County Results
Monroe
  70–80%
  80–90%
  90-100%


President before election

James Monroe
Democratic-Republican

Elected President

James Monroe
Democratic-Republican

During this election, James Monroe was re-elected by a large margin. Pennsylvania voted for Monroe over opposition candidate DeWitt Clinton.

Results edit

1820 United States presidential election in Pennsylvania[2]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Monroe (incumbent) 30,313 94.12% 24[1]
Independent DeWitt Clinton 1,893 5.88% 0
Totals 32,206 100.0% 24

Note: Election results totals only include known numbers, as verified by the source. Vote totals from several counties are missing/unknown.

See also edit

References edit

  1. ^ a b "1820 ELECTION FOR THE NINTH TERM, 1821-1825". National Archives. Retrieved August 4, 2012.
  2. ^ "Pennsylvania Presidential Election Returns 1820". Wilkes University. Retrieved August 4, 2012.