1812 United States presidential election in Vermont

Summary

The 1812 United States presidential election in Vermont took place between October 30 and December 2, 1812, as part of the 1812 United States presidential election. The state legislature chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

1812 United States presidential election in Vermont

← 1808 October 30 – December 2, 1812 1816 →
 
Nominee James Madison
Party Democratic-Republican
Home state Virginia
Running mate Elbridge Gerry
Electoral vote 8
Percentage 100%

President before election

James Madison
Democratic-Republican

Elected President

James Madison
Democratic-Republican

During this election, Vermont cast its eight electoral votes to Democratic Republican candidate and incumbent President James Madison.[1] For the second time in the state's history, Vermont became the only state in New England to vote for Madison, as the other four New England states cast their electoral votes for Federalist supported candidate DeWitt Clinton.

See also edit

References edit

  1. ^ "1812 | The American Presidency Project". www.presidency.ucsb.edu. Retrieved February 7, 2023.