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1812 United States presidential election in Connecticut

Summary

The 1812 United States presidential election in Connecticut took place between October 30 and December 2, 1812, as part of the 1812 United States presidential election. The state legislature chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

1812 United States presidential election in Connecticut
← 1808 October 30 – December 2, 1812 1816 →
 
Nominee DeWitt Clinton
Party Democratic-Republican[a]
Alliance Federalist
Home state New York
Running mate Jared Ingersoll
Electoral vote 9
Percentage 100%
President before election

James Madison
Democratic-Republican

Elected President

James Madison
Democratic-Republican

During this election, Connecticut cast its nine electoral votes to Independent Democratic-Republican and Federalist-supported candidate DeWitt Clinton. Nationally, traditional Democratic Republican candidate and incumbent President James Madison won by a narrow margin.

See also edit

Notes edit

  1. ^ While commonly labeled as the Federalist candidate, Clinton technically ran as a Democratic-Republican and was not nominated by the Federalist party itself, the latter simply deciding not to field a candidate. This did not prevent endorsements from state Federalist parties (such as in Pennsylvania), but he received the endorsement from the New York state Democratic-Republicans as well.

References edit

  1. ^ Congressional Quarterly's guide to US elections (2. ed.). Washington, D.C: Congressional Quarterly. 1985. pp. 254–256. ISBN 9780871873392. Retrieved July 3, 2023.