1808 United States presidential election in Vermont

Summary

The 1808 United States presidential election in Vermont took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. The state legislature chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

1808 United States presidential election in Vermont

← 1804 November 4 - December 7, 1808 1812 →
 
Nominee James Madison
Party Democratic-Republican
Home state Virginia
Running mate George Clinton
Electoral vote 6
Percentage 100%

President before election

Thomas Jefferson
Democratic-Republican

Elected President

James Madison
Democratic-Republican

During this election, Vermont cast its six electoral votes to Democratic Republican candidate and Secretary of State James Madison.[1][2] As the other four New England states cast their electoral votes for Federalist candidate Charles Cotesworth Pinckney, Vermont became the only state in New England to vote for Madison.

See also edit

References edit

  1. ^ "1808 | The American Presidency Project". www.presidency.ucsb.edu. Retrieved February 7, 2023.
  2. ^ Vermont Office of Secretary of State (1917). Vermont Legislative Directory. Rand, Avery. p. 77.