1808 United States presidential election in New Jersey

Summary

The 1808 United States presidential election in New Jersey took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. The state chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

1808 United States presidential election in New Jersey

← 1804 November 4 - December 7, 1808 1812 →
 
Nominee James Madison Charles C. Pinckney
Party Democratic-Republican Federalist
Home state Virginia South Carolina
Running mate George Clinton Rufus King
Electoral vote 8 0
Popular vote 18,670 14,687
Percentage 55.97% 44.03%

President before election

Thomas Jefferson
Democratic-Republican

Elected President

James Madison
Democratic-Republican

During this election, New Jersey cast its eight electoral votes to Democratic Republican candidate and Secretary of State James Madison.[1]

See also edit

References edit

  1. ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. p. 15. ISBN 9780786410170.