1808 United States presidential election in Connecticut

Summary

The 1808 United States presidential election in Connecticut took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. The state legislature chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

1808 United States presidential election in Connecticut

← 1804 November 4 - December 7, 1808 1812 →
 
Nominee Charles C. Pinckney
Party Federalist
Home state South Carolina
Running mate Rufus King
Electoral vote 9
Percentage 100%

President before election

Thomas Jefferson
Democratic-Republican

Elected President

James Madison
Democratic-Republican

During this election, Connecticut cast its nine electoral votes to Federalist candidate Charles Cotesworth Pinckney. 4 of the 5 New England states voted for Pinckney, barring Vermont, which voted for Democratic Republican candidate and Secretary of State James Madison, who nationally won the election.

See also edit

References edit

  1. ^ Congressional Quarterly's guide to US elections (2. ed.). Washington, D.C: Congressional Quarterly. 1985. pp. 254–256. ISBN 9780871873392. Retrieved July 3, 2023.