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1806 United States elections 
Summary
The 1806 United States elections occurred in the middle of Democratic-Republican President Thomas Jefferson's second term, during the First Party System. Members of the 10th United States Congress were chosen in this election. Neither chamber saw significant partisan change, with the Democratic-Republicans retaining a commanding majority in both the House and Senate.[3][4]
| ← 1804 1805 1806 1807 1808 → Midterm elections | |
| Incumbent president | Thomas Jefferson (Democratic-Republican) |
|---|---|
| Next Congress | 10th |
| Senate elections | |
| Overall control | Democratic-Republican hold |
| Seats contested | 11 of 34 seats[1] |
| Net seat change | Democratic-Republican +1[2] |
| House elections | |
| Overall control | Democratic-Republican hold |
| Seats contested | All 142 voting seats |
| Net seat change | Democratic-Republican +2[2] |
See also edit
References edit
- ^ Not counting special elections.
- ^ a b Congressional seat gain figures only reflect the results of the regularly-scheduled elections, and do not take special elections into account.
- ^ "Party Divisions of the House of Representatives". United States House of Representatives. Retrieved 25 June 2014.
- ^ "Party Division in the Senate, 1789-Present". United States Senate. Retrieved 25 June 2014.