1800 United States presidential election in Connecticut

Summary

The 1800 United States presidential election in Connecticut took place between October 31 and December 3, 1800, as part of the 1800 United States presidential election. The state legislature chose nine representatives, or electors, to the Electoral College, who voted for President and Vice President.[1]

1800 United States presidential election in Connecticut

← 1796 October 31 - December 3, 1800 1804 →
 
Nominee John Adams Charles C. Pinckney
Party Federalist Federalist
Home state Massachusetts South Carolina
Electoral vote 9 9
Percentage 100.00%

President before election

John Adams
Federalist

Elected President

Thomas Jefferson
Democratic-Republican

Connecticut cast nine electoral votes for incumbent Federalist President and New England native John Adams. However, Adams would lose to Democratic-Republican candidate Thomas Jefferson nationally.

See also edit

References edit

  1. ^ Congressional Quarterly's guide to US elections (2. ed.). Washington, D.C: Congressional Quarterly. 1985. pp. 254–256. ISBN 9780871873392. Retrieved July 3, 2023.